look at the semicircle
area of semicircle
[tex]{ \boxed{ \bold{ \red{A = \pi \: \times {r}^{2} }}}}[/tex]
[tex]{ \bold{ \boxed{ \red{radius = \frac{diameter}{2} } }}}[/tex]
[tex]radius = \frac{8}{2} = \boxed{4}[/tex]
[tex]area = 3.14 \times {4}^{2} \\ area = 50.24[/tex]
as we can see that is a parallelogram
so ,
area of parallelogram
[tex] \boxed {\bold{ \red{area \: of \: parallelogram =b \times h }}}[/tex]
[tex]area \: = 8 \times 10 \\ are \: = 80in[/tex]
area of fig = area of semicircle + area of parallelogram
total area = 50.24+80
total area = 130.24 in²
[tex] \boxed{130.24 {in}^{2} }[/tex]
