Answer:
63.245 feet.
Step-by-step explanation:
Given:
A model of a pyramid being built for the San Antonio Zoo enclosed butterfly exhibit has a right triangular base.
If the two legs of the triangular base measure 20 feet and 60 feet.
Question asked:
How long is the hypotenuse? ( Let [tex]h[/tex] )
Solution:
Here base and height of a right angled triangle is given and we have to find the longest side that is hypotenuse.
As we know:
By Pythagoras Theorem:
Square of hypotenuse = Square of base + Square of height of right angled triangle
[tex]h^{2} =20^{2} +60^{2} \\h^{2} =400 +3600\\h^{2} =4000\\\\Taking\ root\ both\ sides\\\\ \sqrt[2]{h^{2} } =\sqrt[2]{4000} \\ \\ h=63.245\ feet[/tex]
Thus, hypotenuse of a right triangular base is 63.245 feet.
