Given the balanced equation:

ZnSO4 + SrCl2 ------> SrSO4 + ZnCl2

What number of moles of SrCl2 is consumed when 54 g of ZnCl2 is produced?

a) 0.16 b) 0.3 c) 0.79 d) 1.58 e) 0.4

Respuesta :

Neetoo

Answer:

0.4

Explanation:

Given data:

Number of moles of SrCl₂ consumed = ?

Mass of ZnCl₂ produced = 54 g

Solution:

Chemical equation:

ZnSO₄ + SrCl₂    →    SrSO₄ +  ZnCl₂

Number of moles of ZnCl₂:

Number of moles = mass/ molar mass

Number of moles = 54 g/136.3 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of  ZnCl₂ with SrCl₂  from balance chemical equation.

                          ZnCl₂              :             SrCl₂

                              1                  :                1

                           0.4                 :              0.4

Thus when 54 g of  ZnCl₂ produced 0.4 moles of SrCl₂ react.

The moles of [tex]\rm SrCl_2[/tex]. consumed by 54 grams of zinc chloride has been 0.4 moles. Thus the correct option is e.

From the given balanced equation, 1 mole of [tex]\rm ZnCl_2[/tex] consumes 1 mole of [tex]\rm SrCl_2[/tex].

The molecular weight of [tex]\rm ZnCl_2[/tex] = 136.28 g/mol

The moles of [tex]\rm ZnCl_2[/tex] in 54 g:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of [tex]\rm ZnCl_2[/tex] = [tex]\rm \dfrac{54}{136.28}[/tex] mol

Moles of [tex]\rm ZnCl_2[/tex] = 0.4 mol

Since, 1 mole [tex]\rm ZnCl_2[/tex] = 1 mole  [tex]\rm SrCl_2[/tex].

0.4 mol [tex]\rm ZnCl_2[/tex] = 0.4 mole [tex]\rm SrCl_2[/tex].

Thus, the moles of [tex]\rm SrCl_2[/tex]. consumed by 54 grams of zinc chloride has been 0.4 moles. Thus the correct option is e.

For more information about the balanced chemical equation, refer to the link:

https://brainly.com/question/7181548