Answer:
The wavelength of the incident light is [tex]\lambda =[/tex] 400 nm
Explanation:
Given data
Distance between the sits
[tex]d = \frac{0.075}{50000}[/tex]
d = 1.5 × [tex]10^{-6}[/tex] m
[tex]\theta = 32.5[/tex]°
m = 2
We know that the wavelength of the incident light is given by
[tex]\lambda = \frac{d\sin \theta}{m}[/tex]
Put all the value in above formula we get
[tex]\lambda = \frac{1.5 (\sin 32.5)}{2}[/tex]×[tex]10^{-6}[/tex]
[tex]\lambda =[/tex] 4 × [tex]10^{-7}[/tex] m
[tex]\lambda =[/tex] 400 nm
Therefore the wavelength of the incident light is [tex]\lambda =[/tex] 400 nm
