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Hydrochloric acid and sodium hydroxide react as follows:
HCl+NaOH+H20+NaCl
Calculate the mass of NaCl formed when 40.0 grams of HCland 40.0 grams of NaOH react.

Please help me out here:)

Respuesta :

joseaaronlara

Answer:

The answer to your question is 58.5 g of NaCl

Explanation:

Data

mass of NaCl = ?

mass of HCl = 40 g

mass of NaOH = 40 g

Balanced chemical reaction

               HCl  +  NaOH  ⇒   H₂O  +  NaCl

-Calculate the molar mass of the reactants

HCl = 1 + 35.5 = 36.5 g

NaOH = 23 + 16 + 1 = 40 g

-Calculate the limiting reactant

theoretical proportion = HCl/NaOH = 36.5 / 40 = 0.9125

experimental proportion = HCl / NaOH = 40 / 40 = 1

As the experimental proportion was higher than the theoretical proportion, the limiting reactant is NaOH.

-Calculate the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5

-Calculate the experimental mass of NaCl

                   40 g of NaOH -------------------- 58.5 g of NaCl

                   40 g of NaOH -------------------  x

                    x = (40 x 58.5) / 40

                    x = 58.5 g of NaCl

The mass of NaCl formed should be 58.5g.

Calculation of the mass:

Since

mass of HCl = 40 g

mass of NaOH = 40 g

We know that the balance chemical reaction should be

              HCl  +  NaOH  ⇒   H₂O  +  NaCl

Now the molar mass of the reactants should be

HCl = 1 + 35.5 = 36.5 g

NaOH = 23 + 16 + 1 = 40 g

Now the limiting reactant should be

theoretical proportion = HCl/NaOH = 36.5 / 40 = 0.9125

experimental proportion = HCl / NaOH = 40 / 40 = 1

Now the molar mass should be

NaCl

= 23 + 35.5

= 58.5

Learn more about mass here: https://brainly.com/question/13384700

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