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As a particle moves along an x axis, a force in the positive direction of the axis acts on it. The plot shows the magnitude F of the force versus position x of the particle. The curve is given by F = a/x2, with a = 9.0 N·m2. Find the work done on the particle by the force as the particle moves from x = 1.0 m to x = 3.0 m by integrating the force function.

Respuesta :

Answer:

The work done on the particle is 6 J

Explanation:

The work done on the particle is equal to:

[tex]W=\int\limits^3_1 {Fx} \, dx =\int\limits^3_1 {\frac{a}{x^{2} } } \, dx =a\int\limits^3_1 {\frac{dx}{x^{2} } } \, \\W=9(\frac{-1}{x} )_{1}^{3} =-9(\frac{1}{3} -1)=6J[/tex]

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