Answer:
The volleyball travel high enough to clear the top of the net.
Step-by-step explanation:
The height of a volleyball, h, in feet, is given by h = −16t² + 11t + 5.5, where t is the number of seconds after it has been hit by a player.
Now, for h = 7.3 feet, we can write
7.3 = - 16t² + 11t + 5.5
⇒ 16t² - 11y + 1.8 = 0
Using the quadratic formula we get,
[tex]t = \frac{- (- 11) \pm \sqrt{(-11)^{2} - 4(16)(1.8)}}{2(16)}[/tex]
⇒ [tex]t = \frac{11 \pm 2.4}{32}[/tex]
⇒ t = 0.27 or t = 0.42
Therefore, for the two real positive values of t the volleyball travel high enough to clear the top of the net. (Answer)
