Nitration of an aromatic ring involves an electrophilic substitution reaction. Draw the structure of the electrophile that is attacked by the aromatic ring and the intermediate formed after attachment of the electrophile to the ring. Be sure to show formal charges.

The full mechanism of the nitration of an aromatic ring (benzene) is shown in the image attached. The electrophile is NO2^+. It us generated from HNO3/H2SO4. it attacks the benzene ring and leads to the formation of a delocalized intermediate which rearranges to form the product, in this case, nitrobenzene. Note that the intermediate can also be represented by a number of resonance structures.

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codiepienagoya codiepienagoya · Answer 2 · 2022-04-10T22:45:19+02:00

Following are descriptions of making the nitrobenzene, and its creation steps can be defined as follows:

Nitro benzene:

The attached graphic shows all the complete methods of aromatic ring nitration (benzene).
[tex]NO_2^+[/tex] acts as an electrophile [tex]\frac{HNO_3}{H_2SO_4}[/tex] is indeed the source of it.
It assaults on ring structure in this instance, resulting in the creation of a delocalized intermediate that rearranges to generate the product, nitrobenzene in this example.
It is worth noting that the intermediate can take on a variety of resonance configurations.

Find out more about the nitro benzene here:

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