Answer:
The number of turns in secondary coil is 4000
Explanation:
Given:
Current in primary coil [tex]I_{P} = 500[/tex] A
Current in secondary coil [tex]I_{S} = 25[/tex] A
Number of turns in primary coil [tex]N_{P} = 200[/tex]
In case of transformer the relation between current and number of turns is given by,
[tex]\frac{N_{S} }{N_{P} } = \frac{I_{P} }{I_{S} }[/tex]
For finding number of turns in secondary coil,
[tex]N_{S} = \frac{I_{P} }{I_{S} } N_{P}[/tex]
[tex]N_{S} = \frac{500}{25} \times 200[/tex]
[tex]N_{S} = 4000[/tex]
Therefore, the number of turns in secondary coil is 4000
