Answer:
E= 17066.67 k per inch square
Explanation:
given that
Si = 0.5 in,
P= 100k
l = 16ft = 192in
A= 2.25 in²
rp = 125ksi
recalll that strain
E = EL/L
= 0.5/192
= 0.0026
also, stress
r = P/A
=100/2.25
= 44.44ksi
since the stress(r) is less than the proportionality limit
(rp) , Hence the stress will be proportional to strain, from hook;s law and written as
T∝ E
T =E∑
therefore,
Elastic modulus E= (P/A)/(d/l)
E= (100/2.25)/(0.5/192)
E= 17066.67 k per inch square
