Answer:
α = [tex]6bt - 12ct^2[/tex]
Explanation:
The angle, θ, has been given as:
θ = [tex]at + bt^3 -ct^4[/tex]
To obtain angular acceleration, α, we have to differentiate the angle twice, with respect to time, t.
Differentiating once will yield the angular velocity, ω:
ω = dθ/dt = [tex]a + 3bt^2 - 4ct^3[/tex]
This can then be differentiated to obtain angular acceleration:
α = dω/dt = [tex]6bt - 12ct^2[/tex]
