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A standard solution of 0.442 M NaOH was used to determine the concentration of a hydrochloric acid solution. If 43.50 mL of NaOH is needed to neutralize 65.00 mL of the acid, what is the molar concentration of the acid in the original solution

Respuesta :

Answer : The molar concentration of the acid in the original solution is, 0.296 M

Explanation :

Formula used :

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume of HCl.

[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume of NaOH.

We are given:

[tex]M_1=?\\V_1=65.00mL\\M_2=0.442M\\V_2=43.50mL[/tex]

Now put all the given values in above equation, we get:

[tex]M_1\times 65.00mL=0.442M\times 43.50mL\\\\M_1=0.296M[/tex]

Hence, the molar concentration of the acid in the original solution is, 0.296 M

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