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A small sphere of radius R is arranged to pulsate so that its radius varies in simple harmonic motion between a minimum of R−x and a maximum of R+x with frequency f. This produces sound waves in the surrounding air of density rho and bulk modulus B.


a- Find the intensity of sound waves at the surface of the sphere. (The amplitude of oscillation of the sphere is the same as that of the air at the surface of the sphere.)


b-Find the total acoustic power radiated by the sphere


c-At a distance d≫R from the center of the sphere, find the amplitude of the sound wave.


d-At a distance d≫R from the center of the sphere, find the pressure amplitude of the sound wave.


e-At a distance d≫R from the center of the sphere, find the intensity of the sound wave.


Express your answer in terms of the variables R, x, f, and appropriate constants.

Respuesta :

Answer:

The intensity of sound wave at the surface of the sphere [tex]I = \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }[/tex]

Explanation:

B = Bulk modulus

Intensity, [tex]I = \frac{P_{max} ^{2} }{2\sqrt{\rho B} }[/tex]

The amplitude of oscillation of the sphere is given by:

[tex]P_{max} = BkA\\k = \frac{2\pi }{\lambda} \\[/tex]

[tex]A = \triangle R\\[/tex]

Substitute v and A into Pmax

[tex]P_{max} = (2\pi f)\sqrt{\rho B} \triangle R\\ P_{max} ^{2} = 4\pi^{2} *f^{2} \rho B (\triangle R)^{2}[/tex]

[tex]I = \frac{ 4\pi^{2} f^{2} \rho B (\triangle R)^{2}}{2\sqrt{\rho B} }[/tex]

[tex]P_{total} = 4\pi R^{2} I[/tex]

[tex]P_{total} =4\pi R^{2} \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} }[/tex]

The intensity of the sound wave at a distance  is given by:

[tex]I = \frac{P_{total} }{4\pi d^{2} }[/tex]

[tex]I = 4\pi R^{2} \frac{ 2\pi^{2} f^{2} \rho B (\triangle R)^{2}}{\sqrt{\rho B} } * \frac{1}{4\pi d^{2} } \\I = \frac{ 2\pi^{2}R^{2} f^{2}\sqrt{\rho B}(\triangle R)^{2}}{ d^{2} }[/tex]

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