Answer:
[tex]\frac{dC}{dQ} \approx 1.25[/tex], [tex]C(101)-C(100) = 1.247[/tex], [tex]\delta = 0.24\,\%[/tex]
Step-by-step explanation:
The marginal cost function is:
[tex]\frac{dC}{dQ} = 12.5\cdot x^{-\frac{1}{2} }[/tex]
The marginal cost for 100 books is:
[tex]\frac{dC}{dQ} \approx 1.25[/tex]
The difference is:
[tex]C(101)-C(100) = 25\cdot (101^{\frac{1}{2} }-100^{\frac{1}{2} })[/tex]
[tex]C(101)-C(100) = 1.247[/tex]
The relative error is:
[tex]\delta = \frac{|1.25-1.247|}{1.25}\times 100\,\%[/tex]
[tex]\delta = 0.24\,\%[/tex]
