A hockey team is revealing their championship banner outside their stadium. The banner is in the shape of a triangle with

a height that is 4 times as tall as the base length of the banner. If the total area of the banner is 18 square meters (18 m²),

what is the length of the base of the banner in meters?

The area (A) of a triangle is A = I x base x height.

Respuesta :

Answer : The length of the base of the banner is, 9 m

Step-by-step explanation :

Let the base length of the banner be, x

So, the height of the banner will be, 4x

Formula used :

Area of triangle = [tex]\frac{1}{2}\times Base\times Height[/tex]

Given:

Area of triangle = 18 m²

Area of triangle = [tex]\frac{1}{2}\times Base\times Height[/tex]

18 m² = [tex]\frac{1}{2}\times (x)\times (4x)[/tex]

[tex]18m^2=2x^2[/tex]

[tex]x=3m[/tex]

Length of the base of the banner = x = 9 m

Height of the banner = 4x = 4 × 9 = 36 m

Therefore, the length of the base of the banner is, 9 m