After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

A. C(t)=28,000(0.811)t
B. C(t)=28,000(1.575)t
C. C(t)=28,000(0.158)t
D. C(t)=28,000(0.189)t

The value of the car is decreasing. Thus, by the end of the first year of ownership, the car will have the value $28,000(1 -0.189)^1, where the "-0.189" represents DECAY instead of GROWTH.

Please use " ^ " to indicate exponentiation.

Then the desired formula is C(t) = $28,000(0.811)^t (Answer A)

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After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually. Which function describes the value of the car after t years? A. C(t)=28,000(0.811)t B. C(t)=28,000(1.575)t C. C(t)=28,000(0.158)t D. C(t)=28,000(0.189)t

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After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually.

Which function describes the value of the car after t years?

A. C(t)=28,000(0.811)t
B. C(t)=28,000(1.575)t
C. C(t)=28,000(0.158)t
D. C(t)=28,000(0.189)t