Answer:
8.08 × [tex]10^{22}[/tex] atoms of hydrogen
Explanation:
From the given data, we have two categories of variables (unknowns):
The longer route would be to solve for these variables first, by determining the number of moles of the Caffeine sample (0.134 moles of C8H10N4O2) from the mass of carbon (12.89 g = 1.07 moles in 6.47 [tex]10^{22}[/tex] atoms) provided. And then solve for the number of atoms of H. [N.B: 1 mole of ANY substance = 6.022 × [tex]10^{22}[/tex] atoms ]
Alternatively and quicker, we can use the mole ratios of the Carbon:Hydrogen atoms in the compound.
8 : 10 ≡ 4 : 5
If 4 moles -- 6.47 [tex]10^{22}[/tex] atoms
Then 5 moles -- ?? atoms
⇒ No. of atoms of Hydrogen = [tex]\frac{5*6.47*10^{22}}{4}[/tex]
=8.08 × [tex]10^{22}[/tex] atoms of hydrogen
[tex]8.08*10^{22}[/tex] atoms of hydrogen
Given:
Amount (moles or mass) of Caffeine( C₈H₁₀N₄O₂) = [tex]6.47*10^{22}[/tex]
To find:
Amount (moles or mass) of Hydrogen=?
We can solve this by using the mole ratio concept:
Carbon: Hydrogen atoms in the compound.
8 : 10 ≡ 4 : 5
If , 4 moles → [tex]6.47*10^{22}[/tex] atoms
Then 5 moles → ?? atoms
⇒ No. of atoms of Hydrogen = [tex]\frac{5*6.47*10^{22}}{4} =8.08*10^{22}[/tex] atoms of hydrogen
Thus, [tex]8.08*10^{22}[/tex] atoms of hydrogen are present in the sample.
Find more information about "Number of moles" here:
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