Answer:
Explanation:
We shall apply gas law formula
P₁V₁ / T₁ = P₂V₂/T₂
P₁ , V₁ , T₁ are initial pressure , volume and temperature and P₂ , V₂, T₂ are final pressure , volume and temperature of the gas
P₁ = 751 mmHg , P₂ = .511 x 760 mmHg = 388.36 mmHg
T₁ = 273 + 25 = 298K , T₂ = 273 - 2.01 = 270.93 K
V₁ = 53 L , P₂ = ?
Putting the given values in the equation
751 x 53 / (273 +25) = 388.36 x V₂ / 270.93
V₂ = 93.18 L .
The weather balloon's volume at the higher altitude is 93.18L
According to the general gas equation is expressed as:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
[tex]P_1 \ and \ P_2[/tex] are the pressure of the gas:
[tex]V_1 \ and \ V_2[/tex] are the volume of the gas
[tex]T_1 \ and \ T_2[/tex] are the temperatures
Given the following parameters
P₁ = 751mmHg
P₂ = 0.511 * 760 = 388.36mmHg
V₁ = 53.0L
V₂ = ?
T₁ = 25 + 273 = 298K
T₂ = -2.01 + 273 = 270.99K
Substitute the given parameters into the formula:
[tex]V_2=\frac{P_1V_1T_2}{P_2T_1} \\V_2=\frac{751\times53\times270.99}{388.36\times298}\\V_2=93.18L[/tex]
Hence the weather balloon's volume at the higher altitude is 93.18L
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