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A farmer is comparing the number of eggs laid by two hens. The first hen laid 6 eggs per week for x weeks. The second hen laid 9 eggs per week for y weeks. The total number of eggs laid by the first hen was greater than the total number of eggs laid by the second hen. Write an inequality showing this relationship.

Respuesta :

The needed inequality is (6 X)   > (9 Y) .

Step-by-step explanation:

According to the given data:

The number of eggs laid by first hen per week = 6 eggs

So, the number of eggs laid by first hen in X weeks

= (Eggs Laid per week) x  (X)   = 6 X

So, the first hen lays a total of (6 X) eggs in X weeks.

Similarly,

The number of eggs laid by second hen per week =  9  eggs

So, the number of eggs laid by second hen in Y weeks

= (Eggs Laid per week) x  (Y)   = 9 Y

So, the second hen lays a total of (9 Y) eggs in Y weeks.

As given:

The total number of eggs laid by the first hen >  The total number of eggs laid by the second hen.

⇒ (6 X)   > (9 Y)  

Hence, the needed inequality is (6 X)   > (9 Y) .

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