Answer:
V₂ = 5.92 L
Explanation:
Given data:
Initial volume of methane = 7.0 L
Initial temperature = 50.0°C
Final temperature = 0°C
Final volume = ?
Solution:
Initial temperature = 50.0°C (50+273 = 323 K)
Final temperature = 0°C (0+273 = 273 K)
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 7 L × 273 K / 323 k
V₂ = 1911 L.K / 323 K
V₂ = 5.92 L
