Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power. x10z7 x14z15 1 over x to the 10th power times z to the 7th power 1 over x to the 14th power times z to the 15th power

Respuesta :

Answer:

The option A) [tex]x^{10}z^7[/tex] is correct answer.

The correct simplification for the given expression [tex]\frac{x^{12}\times z^{11}}{x^2\times z^4}[/tex] is [tex]x^{10}z^7[/tex]

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as [tex]\frac{x^{12}\times z^{11}}{x^2\times z^4}[/tex]

To choose the correct simplification of the given expression :

Now we have to simplify the given expression as below

[tex]\frac{x^{12}\times z^{11}}{x^2\times z^4}[/tex]

[tex]=x^{12}\times z^{11}(x^{-2}\times z^{-4})[/tex]   ( by using the identity [tex]\frac{1}{a^m}=a^{-m}[/tex] )

[tex]=(x^{12}.x^{-2})\times (z^{11}.z^{-4})[/tex]

[tex]=x^{12-2}\times z^{11-4}[/tex] ( by using the identity [tex]a^m.a^n=a^{m+n}[/tex] )

[tex]=x^{10}\times z^7[/tex]

[tex]=x^{10}z^7[/tex]

[tex]\frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7[/tex]

The correct simplification for the given expression [tex]\frac{x^{12}\times z^{11}}{x^2\times z^4}[/tex] is [tex]x^{10}z^7[/tex]

Hence option A) [tex]x^{10}z^7[/tex] is correct answer.

Answer:

A)  is correct answer.

Step-by-step explanation:

I took the FLVS  Algebra 1 lesson 6.08 quiz