Respuesta :
Answer:
T final = 71.5°C
Explanation:
- Q= mCΔT
∴ Q = 10050 J
∴ C copper 20°C = 387 P/Kg°C ≅ 390.268 J/KgK
∴ m copper ? 500 g = 0.500 Kg
∴ T1 = 20°C ≅ 293 K
∴ T2 = ?
⇒ ΔT = T2 - T1 = Q / m C = (10050 J) / ((0.500 Kg)(390.268 J/KgK))
⇒ T2 - 293 K = 51.503 K
⇒ T2 = 293 K + 51.503 K
⇒ T2 = 344.503 K ≅ 71.503°C
Answer:
The final temperature is 71.94 °C
Explanation:
Step 1: Data given
Mass of the copper bar = 500 grams
The specific heat of copper = 387 J/kg°C = 0.387 J/g°C
The initial temperature = 20.0 °C
Heat removed = 10050 J
Step 2: Calculate the final temperature
Q = m*c * ΔT
⇒with Q = the heat removed = 10050 J
⇒with m = the mass of the barr of copper = 500 grams
⇒with c= the specific heat of copper = 0.387 J/g°C
⇒with ΔT = the change of temperature = T2 -T1
10050 = 500 * 0.387 * ΔT
ΔT = 10050 / (500*0.387)
ΔT = 51.94 °C
Step 3: Calculate the final temperature
ΔT = T2 - T1
⇒with ΔT = the change of temperature = 51.94 °C
⇒with T2 = the final temperature = TO BE DETERMINED
⇒with T1 = the initial temperature = 20.0 °C
51.94 °C = T2 - 20.0°C
T2 = 51.94 °C + 20.0 °C
T2 = 71.94 °C
The final temperature is 71.94 °C
