Answer : The new volume of gas is, 0.342 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 155 kPa
[tex]P_2[/tex] = final pressure of gas = 605 kPa
[tex]V_1[/tex] = initial volume of gas = 1.00 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]25^oC=273+25=298K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]125^oC=273+125=398K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{155kPa\times 1.00L}{298K}=\frac{605kPa\times V_2}{398K}[/tex]
[tex]V_2=0.342L[/tex]
Therefore, the new volume of gas is, 0.342 L
