Calculate the ph of a buffer that is 0.94 mhc2h3o2 and 0.059 mnac2h3o2. the ka for hc2h3o2 is 1.8×10−5. calculate the of a buffer that is 0.94 and 0.059 . the for is . 2.86 3.54 4.74 1.80 5.97

Respuesta :

Answer:

The pH of the buffer is 3.54.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

[tex]pH=pK_a+\log(\frac{[salt]}{[acid]})[/tex]

[tex]pH=pK_a+\log(\frac{[NaHCO_3]}{[H_2CO_3]})[/tex]

We are given:

[tex]pK_a[/tex] = negative logarithm of acid dissociation constant of carbonic acid

[tex]pK_a=-\log[K_a]=-\[1.8\times 10^{-5}]=4.74[/tex]

[tex][NaC_2H_3O_2]=0.059 M[/tex]

[tex][HC_2H_3O_2]=0.94 M[/tex]

pH = ?

Putting values in above equation, we get:

[tex]pH=4.74+\log(\frac{0.059 M}{0.94})\\\\pH=3.537\approx 3.54[/tex]

The pH of the buffer is 3.54.