Respuesta :
If Kate is measuring the average amount of meteors per minute, then having the ten in there compared to say the 4, it will create an uneven balance in the average, however if she is using a median or the other method, it will not greatly matter.
Seeing 10 meteors increases the mean by 0.67 and the standard deviation is decreased by 0.1
How is the mean affected?
We know that in the first 5 minutes, the number of meteors seen are:
{6, 4, 10, 3, 7}
For these values, the mean is:
[tex]M = \frac{6 + 4 + 10 + 3 + 7}{5} = 6[/tex]
The standard deviation is:
[tex]S = \sqrt{\frac{(6 - 6)^2 + (6 - 4)^2 + (6 - 10)^2 + (6 - 3)^2 + (6 - 7)^2}{5} } = 2.4[/tex]
Now, if we add another element to the set (the 10 asteroids for the next minute) the set becomes:
{6, 4, 10, 3, 7, 10}
And the new mean is:
[tex]M' = \frac{6 + 4 + 10 + 3 + 7 + 10}{6} = 6.67[/tex]
Now the standard deviation is:
[tex]S' = \sqrt{\frac{(6 - 6.67)^2 + (4 - 6.67)^2 + (10 - 6.67)^2 + (3 - 6.67)^2 + (7 - 6.67)^2 + (10 - 6.67)^2}{6} } = 2.3[/tex]
So the mean is increased by 0.67 and the standard deviation decreased by 0.1
If you want to learn more about averages and means:
https://brainly.com/question/20118982
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