Respuesta :
All you need to do is change the point st which the line crosses the y-axis. 1/2x + will work.
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they need to have the same slope.
[tex]y=\frac{1}{2} x+2[/tex] The slope is 2, so the parallel line's slope is also 2.
Now that you know the slope, substitute/plug it into the equation:
y = mx + b
[tex]y=\frac{1}{2} x+b[/tex] To find b, plug in the point (2, -3) into the equation, then isolate/get the variable "b" by itself
[tex]-3=\frac{1}{2}(2)+b[/tex]
-3 = 1 + b Subtract 1 on both sides to get "b" by itself
-3 - 1 = 1 - 1 + b
-4 = b
[tex]y=\frac{1}{2} x-4[/tex]
