Answer:
12.04x10^23
Explanation:
I mole of a substance contains 6.022x10^23
Here, Molar mass of O = 16u
And molar mass of 02 32u
And 32g of 02 = 1 mole of 02
Therefore 32g of 02 has molecules = 6.022x10^23
Since 1 molecule of 02 has 2 atoms
Therefore 32g of 02 has atoms=2*6.02x10*23
= 12.04x10^23
Answer:
Therefore, any element that contains 8.60 × 10^23 molecules contain the same number of molecules as 32 litres of O2 at STP.
Explanation:
At STP(standard temperature and pressure)
The volume of 1 mole of gas is 22.4 litres.
Number of molecules in 1 mole of gas is = 6.022×10^23 molecules/mole
The number of moles of O2 in 32 litres at STP;
n = 32litres ÷ 22.4 litres/mole
n = 1.429 moles of O2.
The number of molecules of O2 in 32 litres at STP is;
N = 32/22.4 moles × 6.022×10^23 molecules/mole
N = 8.60 × 10^23 molecules.
Therefore, any element that contains 8.60 × 10^23 molecules contain the same number of molecules as 32 litres of O2 at STP.
