Answer:
The answer to your question is 0.34 M
Explanation:
Data
[Sr(OH)₂] = ?
Volume of Sr(OH)₂ = 35.6 ml or 0.0356 l
[HBr] = 0.0445 M
Volume of HBr = 0.549 l
Balanced chemical reaction
2HBr + Sr(OH)₂ ⇒ SrBr₂ + 2H₂O
Process
1.- Calculate the moles of HBr
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.0445 x 0.549
= 0.0244
2.- Calculate the moles of Sr(OH)₂ using the coefficients of the balanced reaction
2 moles of HBr ----------------------- 1 mol of Sr(OH)₂
0.0244 moles ----------------------- x
x = (0.0244 x 1) / 2
x = 0.0122 moles of Sr(OH)₂
3.- Calculate the concentration of Sr(OH)₂
Molarity = 0.0122/ 0.0356
-Simplification
Molarity = 0.34
