Respuesta :
The options of the given are:
A. A large diameter myelinated fiber
B. A small diameter myelinated fiber
C. A large unmyelinated fiber
D. A small unmyelinated fiber
E. A small fiber with multiple Schwann cells
Answer: Option A, A large diameter myelinated fiber.
Explanation:
The conduction of the nerve impulse would be greatest in the myelinated fiber because the main function of the myelin sheath is to increase the speed of the impulse at which the electrical signals propagate.
In case of the unmyelinated sheath the nerve impulse travels slowly as the conduction waves but in case of the large diameter myelinated sheath the signals travel via saltatory conduction( hop)
In this type of propagation the signals are transferred from the node of Ranvier in one neuron to next node which increases the overall velocity of the action potentials.
The conduction of nerve impulse would be the fastest in the node of Ranvier.
The given problem is based on the conduction of nerve impulse. The nerve impulse are the signals that are transmitted along the nerve fibre. And the conduction of nerve impulse happens due to presence of charges particles within the signals itself.
- The conduction of the nerve impulse would be greatest in the myelinated fiber because the main function of the myelin sheath is to increase the speed of the impulse at which the electrical signals propagate.
- In case of the unmyelinated sheath the nerve impulse travels slowly as the conduction waves but in case of the large diameter myelinated sheath the signals travel via saltatory conduction( hop)
- In this type of propagation the signals are transferred from the node of Ranvier in one neuron to next node which increases the overall velocity of the action potentials.
Thus, we can conclude that the conduction of nerve impulse would be the fastest in the node of Ranvier.
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