Answer:
The average angle at which the airplane must descend for landing is 21°
Step-by-step explanation:
Here, we have question related to angle of elevation and depression
The height of the airplane be, y = 10,000 ft
The Location of the airport is, x = 50 miles = 26400 ft
Therefore,
we have,
Let the average angle be θ
Therefore,
[tex]tan \theta = \frac{y}{x} = \frac{Opposite}{Adjacent}[/tex]
The opposite to the angle of descent is the height and the adjacent is the distance of the airport away from the airplane
Therefore, tan θ = [tex]\frac{10000}{26400} = 0.379[/tex]
Therefore, the average angle θ = tan⁻¹ 0.379 = 20.746 ° ≈ 21°.
