Respuesta :
Answer:
The frequency of the AC current is 1.51 Hz.
Explanation:
An AC current is given by :
[tex]I=495\sin (9.53 t)[/tex]......(1)
The general equation of AC current is given by :
[tex]I=A\sin (\omega t)[/tex] .....(2)
Comparing equation (1) and (2) we get :
[tex]\omega=9.53[/tex]
We know that,
[tex]2\pi f=9.53\\\\f=\dfrac{9.53}{2\pi}\\\\f=1.51\ Hz[/tex]
So, the frequency of the AC current is 1.51 Hz.
The frequency in Hz of the AC current given by I = 495sin(9.43t) is; f = 1500.83 Hz
The current is given by;
I = 495sin(9.43t)
Now, comparing this equation to the general expression of AC Current which is;
I = A sin ωt
It means that;
A = 495
ω = 9.43 rad/ms
Now we want to find the frequency which is in Hz. Hz is simply cycles/s. Thus, let us convert ω from rad/ms to rad/s to get;
1 rad/ms = 1000 rad/s
Thus: 9.43 rad/ms = 9.43 × 1000/1
ω = 9430 rad/s
Now, we know that formula for angular velocity is;
ω = 2πf
Thus;
f = ω/2π
Plugging in the relevant values;
f = 9430/(2π)
f = 1500.83 Hz
Read more at; https://brainly.com/question/17055416
The complete question is;
An AC current is given by I = 495sin(9.43t), with I in milliamperes and t in milliseconds. Find the frequency in Hz.
