Answer:
20 pi of 62.8 square units
Step-by-step explanation:
[tex]central \: angle \: ( \theta) \\ = \frac{2}{5} {\pi}^{c} = \frac{2}{5} \times 180 \degree = 72 \degree \\ \\ area \: of \: sector \\ = \frac{\theta}{360 \degree} \times area \: of \: circle \\ \\ = \frac{72 \degree}{360 \degree} \times 100\pi \\ \\ = \frac{1}{5} \times 100\pi \\ \\ \red{ \boxed{ \bold{area \: of \: sector= 20\pi \: {units}^{2} }}} \\ \\ = 20 \times 3.14 \\ \\ or \\ \\ \purple{ \boxed{ \bold{area \: of \: sector = 62.8 \: {units}^{2} }}}[/tex]
