Respuesta :
Answer:
M Na2S = 2 M
Explanation:
- molarity (M) [=] mol/L sln
∴ mass Na2S = 156 g
∴ molar mass Na2S = 78.0452 g/mol
⇒ mol Na2S = (156 g)*(mol/78.0452 g) = 1.9988 mol ≅ 2 mol
∴ volume sln = 1000 mL = 1 L
molarity (M):
⇒ M Na2S = 2 mol / 1 L
⇒ M Na2S = 2 M
Answer:
The molarity of the Na2S solution is 2.00 M
Explanation:
Step 1: Data given
Sodium sulfide = Na2S
Mass of sodium sulfide = 156.0 grams
Molar mass of sodium sulfide (Na2S) = 78.0452 g/mol
Volume = 1000 mL = 1.0 L
Step 2: Calculate moles of sodium sulfide (Na2S)
Moles Na2S = mass Na2S / molar mass Na2S
Moles Na2S = 156.0 grams / 78.0452 g/mol
Moles Na2S = 1.999 moles
Step 3: Calculate molarity Na2S solution
Molarity Na2S solution = moles Na2S / volume solution
Molarity Na2S solution = 1.999 moles / 1.0 L
Molarity Na2S solution = 1.999 M ≈ 2.00 M
The molarity of the Na2S solution is 2.00 M
