Respuesta :
Answer:
1. V=19.3 ml
2. mass=74.8g
3. molarity of dilted solution=0.463M
Explanation:
1.
First calculate the mole ,
given mass=53g
molecular weight=98g/mole
[tex]mole=\frac{given mass }{molecular mass}[/tex]
mole=0.54
molarity=28M
[tex]molarity =\frac{mole}{volume in L}[/tex]
[tex]28mol/L=\frac{0.54}{V}[/tex]
V=19.285ml
V=19.3 ml
2.
First calculate the mole of calcium hydroxide,
molariy=1.9M
volume=532 ml=0.532L
[tex]mole=molarity\times volume in L[/tex]
mole=1.01 mol;
[tex]mass = mole\times molecular weight[/tex]
molecular weight of calcium hydroxide= 74g/mol
mass=74.8g
3.
First calculate the mole before adding water
molariy=0.505M
initial volume=124 ml=0.124L
[tex]mole=molarity\times initial volume in L[/tex]
mole=0.063 mol;
after dilution volume=136 ml =0.136L
quantity of solute remains unchanged during dilution of solution.
[tex]Molarity of diluted solution=\frac{mole}{new volume}[/tex]
molarity of dilted solution=0.463M
