Answer:
201.4kg of Fe are produced
Explanation:
The reaction of iron oxide with carbon is:
Fe₂O₃ + ³/₂C → 2 Fe + ³/₂CO₂
288kg of Fe₂O₃ are:
288kg Fe₂O₃ × (1kmol / 159.7kg) = 1.80kmol Fe₂O₃
As 1 mole of Fe₂O₃ reacts producing 2 moles of Fe:
1.80kmol Fe₂O₃ × (2 kmol Fe / 1 kmol Fe₂O₃) = 3.6 kmol Fe. In grams:
3.6kmol Fe × (55.845kg / kmol) = 201.4kg of Fe are produced
