Many relations in biology are expressed by power​ functions, known as allometric​ equations, of the form y equals kx Superscript a​, where k and a are constants. The weight of a certain snake is approximately 439 x cubed​grams, where x is its length in meters. If the snake has length 0.5 meters and is growing at the rate of 0.3 meters per​ year, at what rate is the snake gaining​ weight?

Respuesta :

Answer:

The snake is gaining weight at a rate 110.925 gram per year.

Step-by-step explanation:

Give that,

The weight of the snake is [tex]W= 439 x^3[/tex].

[tex]W= 439 x^3[/tex]

Differentiating with respect to t

[tex]\frac{dW}{dt}=493 \times3x^2\frac{dx}{dt}[/tex]

The snake is growing at the rate 0.3 meter per year. That is [tex]\frac{dx}{dt}=0.3[/tex] m per year.

Putting the value of [tex]\frac {dx}{dt}[/tex]

[tex]\therefore \frac{dW}{dt}=493 \times 3x^2\times 0.3[/tex]

The length of the snake is 0.5 meter. i.e x= 0.5

[tex]\therefore \frac{dW}{dt}|_{x=0.5}=493 \times 3(0.5)^2\times 0.3[/tex]

                   =110.925 gram per year

The snake is gaining weight at a rate 110.925 gram per year.