Evaluate the attached integral. The answer I got was [tex]2x^2 -x+5ln\left|x-2\right|+\frac{1}{3}\left(x-2\right)^3-6+C[/tex] , I'm not entirely sure if my method was correct though.

Evaluate the attached integral The answer I got was tex2x2 x5lnleftx2rightfrac13leftx2right36Ctex Im not entirely sure if my method was correct though class=

Respuesta :

Answer:

(⅓)x³ + 3x + 5ln|x - 2| + c

Step-by-step explanation:

(x³ - 2x² + 3x - 6 + 5)/(x - 2)

[x²(x - 2) + 3(x - 2) + 5]/(x - 2)

x² + 3 + 5/(x - 2)

Integral:

⅓x³ + 3x + 5ln|x - 2| + c

Answer:

[tex]=2x^2-x+5\ln \left|x-2\right|+\frac{1}{3}\left(x-2\right)^3-6+C[/tex]

Step-by-step explanation:

[tex]\int \frac{x^3-2x^2+3x-1}{x-2}dx[/tex]

[tex]\frac{x^3-2x^2+3x-1}{x-2}\\[/tex]

[tex]=\frac{x^3}{x-2}-\frac{2x^2}{x-2}+\frac{3x}{x-2}-\frac{1}{x-2}[/tex]

[tex]=\int \frac{x^3}{x-2}dx-\int \frac{2x^2}{x-2}dx+\int \frac{3x}{x-2}dx-\int \frac{1}{x-2}dx[/tex]

[tex]\int \frac{x^3}{x-2}dx[/tex]

[tex]=\int \frac{\left(u+2\right)^3}{u}du; u=x-2[/tex]

[tex]\frac{\left(u+2\right)^3}{u}[/tex]

[tex]\left(u+2\right)^3[/tex]

[tex]=u^3+3u^2\cdot \:2+3u\cdot \:2^2+2^3[/tex]

[tex]=u^3+6u^2+12u+8[/tex]

[tex]=\frac{u^3+6u^2+12u+8}{u}[/tex]

[tex]\frac{u^3+6u^2+12u+8}{u}=\frac{u^3}{u}+\frac{6u^2}{u}+\frac{12u}{u}+\frac{8}{u}[/tex]

[tex]=u^2+\frac{6u^2}{u}+\frac{12u}{u}+\frac{8}{u}[/tex]

[tex]=u^2+6u+\frac{12u}{u}+\frac{8}{u}[/tex]

[tex]=u^2+6u+12+\frac{8}{u}[/tex]

[tex]=\int \:u^2+6u+12+\frac{8}{u}du[/tex]

[tex]=\int \:u^2du+\int \:6udu+\int \:12du+\int \frac{8}{u}du[/tex]

[tex]\int \:u^2du[/tex]

[tex]=\frac{u^{2+1}}{2+1}[/tex]

[tex]=\frac{u^3}{3}[/tex]

[tex]\int \:6udu[/tex]

[tex]=6\cdot \int \:udu[/tex]

[tex]=6\cdot \frac{u^{1+1}}{1+1}[/tex]

[tex]=3u^2[/tex]

[tex]\int \:12du[/tex]

[tex]=12u[/tex]

[tex]\int \frac{8}{u}du[/tex]

[tex]=8\cdot \int \frac{1}{u}du[/tex]

[tex]=8\ln \left|u\right|[/tex]

[tex]=\frac{u^3}{3}+3u^2+12u+8\ln \left|u\right|[/tex]

[tex]=\frac{\left(x-2\right)^3}{3}+3\left(x-2\right)^2+12\left(x-2\right)+8\ln \left|x-2\right|[/tex]

[tex]=3x^2+8\ln \left|x-2\right|+\frac{1}{3}\left(x-2\right)^3-12[/tex]

[tex]\int \frac{2x^2}{x-2}dx[/tex]

[tex]=2\cdot \int \frac{x^2}{x-2}dx[/tex]

[tex]=2\cdot \int \frac{\left(u+2\right)^2}{u}du[/tex]

[tex]\left(u+2\right)^2[/tex]

[tex]=u^2+4u+4[/tex]

[tex]=\frac{u^2+4u+4}{u}[/tex]

[tex]\frac{u^2+4u+4}{u}=\frac{u^2}{u}+\frac{4u}{u}+\frac{4}{u}[/tex]

[tex]=u+\frac{4u}{u}+\frac{4}{u}[/tex]

[tex]=2\cdot \int \:u+4+\frac{4}{u}du[/tex]

[tex]=2\left(\int \:udu+\int \:4du+\int \frac{4}{u}du\right)[/tex]

[tex]\int \:udu[/tex]

[tex]=\frac{u^{1+1}}{1+1}[/tex]

[tex]=\frac{u^2}{2}[/tex]

[tex]\int \:4du[/tex]

[tex]=4u[/tex]

[tex]\int \frac{4}{u}du[/tex]

[tex]=4\cdot \int \frac{1}{u}du[/tex]

[tex]=4\ln \left|u\right|[/tex]

[tex]=2\left(\frac{u^2}{2}+4u+4\ln \left|u\right|\right)[/tex]

[tex]=2\left(\frac{\left(x-2\right)^2}{2}+4\left(x-2\right)+4\ln \left|x-2\right|\right)[/tex]

[tex]2\left(\frac{\left(x-2\right)^2}{2}+4\left(x-2\right)+4\ln \left|x-2\right|\right)[/tex]

[tex]=2\cdot \frac{\left(x-2\right)^2}{2}+2\cdot \:4\left(x-2\right)+2\cdot \:4\ln \left|x-2\right|[/tex]

[tex]=x^2+4x+8\ln \left|x-2\right|-12[/tex]

[tex]\int \frac{3x}{x-2}dx[/tex]

[tex]=3\cdot \int \frac{x}{x-2}dx[/tex]

[tex]=3\cdot \int \frac{u+2}{u}du[/tex]

[tex]=3\cdot \int \:1+\frac{2}{u}du[/tex]

[tex]=3\left(\int \:1du+\int \frac{2}{u}du\right)[/tex]

[tex]\int \:1du[/tex]

[tex]=u[/tex]

[tex]\int \frac{2}{u}du[/tex]

[tex]=2\cdot \int \frac{1}{u}du[/tex]

[tex]=2\ln \left|u\right|[/tex]

[tex]=3\left(u+2\ln \left|u\right|\right)[/tex]

[tex]=3\left(x-2+2\ln \left|x-2\right|\right)[/tex]

[tex]\int \frac{1}{x-2}dx[/tex]

[tex]=\int \frac{1}{u}du[/tex]

[tex]=\ln \left|u\right|[/tex]

[tex]=\ln \left|x-2\right|[/tex]

[tex]3x^2+8\ln \left|x-2\right|+\frac{1}{3}\left(x-2\right)^3-12-\left(x^2+4x+8\ln \left|x-2\right|-12\right)\\+3\left(x-2+2\ln \left|x-2\right|\right)-\ln \left|x-2\right|[/tex]

[tex]=2x^2-x+5\ln \left|x-2\right|+\frac{1}{3}\left(x-2\right)^3-6[/tex]

[tex]=2x^2-x+5\ln \left|x-2\right|+\frac{1}{3}\left(x-2\right)^3-6+C[/tex]