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In humans, hair texture exhibits incomplete dominance. The gene for curly hair (H) is incompletely dominant to the gene for straight hair (h). Individuals that are heterozygous (Hh) have wavy hair.
Two heterozygous parents have a child.
What is the chance that the child will have wavy hair?

Respuesta :

cuttlefishgalore0

Answer:

1/2

Explanation:

the father and mother will have the gene version Hh. with these genes, there are 4 possible combinations:

H from mom and h from dad -> wavy hair

H from mom and H from dad  -> curly hair

h from mom and H from dad -> wavy hair

H from mom and h from dad -> straight hair

2/4, or 1/2, of the possible combinations lead to wavy hair , so there is a 50% chance that their child will have wavy hair.

luisvaschetto

If two heterozygous parents have a child the chance that the child has wavy hair will be 50% (1/2).

  • Incomplete dominance occurs in heterozygous individuals that have different alleles for one given locus which exhibit an intermediate phenotype.

  • In this case, the genetic cross between two heterozygous (Hh) individuals having the 'wavy hair' trait can be exemplified as:

Parental cross:

  • Hh x Hh

Parental gametes (both parents):

  • 1/2 H
  • 1/2 h

Punnett square to determine allele segregation:

            H               h

H       1/4 HH        1/4 Hh

h        1/4 Hh        1/4 hh

In conclusion, if two heterozygous parents have a child the chance that the child has wavy hair will be 50% (1/4 Hh + 1/4 Hh = 1/2 Hh).

Learn more in:

https://brainly.com/question/13402032?referrer=searchResults

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