Answer: 1.09 kPa
Explanation:
Given that,
Original volume V1 = 3.2 L
Original pressure P1 = 2.8 kPa
New pressure P2 = ?
New volume V2 = 8.1 L
Since pressure and volume are given While temperature is constant, apply Boyle's law
P1V1 = P2V2
2.8 kPa x 3.2L = P2 x 8.1L
8.96 kPa L = P2 x 8.2L
P2 = 8.96 kPa L / 8.2L
P2 = 1.09 kPa
Thus, the pressure of the gas would be 1.09 kPa
