Respuesta :
Definitely/Yes.
Factor it yourself and you get x-2.
[tex]x^3-8x^2+14x-4\\= (x-2) (x^2-6x+2)[/tex]
The value of the polynomial function st x = 2 is zero hence x - 2 is a factor of x³-8x²+14x-4.
Given the polynomial function x³-8x²+14x-4. In order to check if x - 2 is a factor, we must show that P(2) = 0
P(x) = x³-8x²+14x-4.
r(x) =x - 2
If r(x) = 0
x - 2 = 0
x = 2
Substitute x = 2 into the polynomail function
P(2) = 2³-8(2)²+14(2)-4
P(2) = 8 - 32 + 28 - 4
P(2) = -24 + 24
P(2) = 0
Since the value of the polynomial function st x = 2 is zero hence x - 2 is a factor of x³-8x²+14x-4.
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