Answer:
Step-by-step explanation:
x-3=0
x=3
find f(3)
or 3(3)³+10(3)²-3-12=81+90-3-12=171-15=156≠0
so x-3 is not a factor.
or
divide the given expression by x-3
From evaluation at x = 3; we may conclude that (x-3) is not a factor of (3x3+10x2-x-12).
If the polynomial (x -3) is a factor of (3x3+10x2-x-12);
Therefore; when x = 3; we have;
3(3)³ + 10(3)² - 3 -12
= 81 + 90 -3 -12
= 156
Since 156 is not equal to 0;
Consequently, (x-3) is not a factor of (3x3+10x2-x-12).
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