15.35 L of gas is at a pressure of 198.0 kpa, then the pressure of gas at the 13.78L volume is 220.55 kpa.
Relation between the pressure and volume of gas will be expressed by the use of ideal gas equation PV = nRT.
For the question, equation becomes:
P₁V₁ = P₂V₂, where
Now putting values from the question on the above equation, we get
P₂ = (198)(15.35) / (13.78) = 220.55 kpa
Hence required value of pressure is 220.55 kpa.
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