Answer:
a(41) = 122
Step-by-step explanation:
Each new term of the given sequence is 3 more than the previous term. Thus, this is an arithmetic sequence with common difference d = 3. Since the first term is 2, the general formula for this arithmetic sequence is a(n) = 2 + 3(n - 1).
For the 41st term of this sequence, a(41) = 2 + 3(41 - 1), or
a(41) = 2 + 120 = 122
