Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust is a Poisson random variable with a mean of 1000. What is the probability that 10 squared centimeters of dust contains more than 10010 particles?
Round your answer to 3 decimal places.

Respuesta :

Using the normal approximation to the Poisson distribution, it is found that there is a 0.460 = 46% probability that 10 squared centimeters of dust contains more than 10010 particles.

What is the Poisson distribution?

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number.
  • [tex]\mu[/tex] is the mean in the given interval.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • The Poisson distribution can be approximated to the normal distribution with the same mean and standard deviation [tex]\sigma = \sqrt{\mu}[/tex].

In this problem, we have that the mean and the standard deviation are given as follows:

[tex]\mu = 10 \times 1000 = 10000, \sigma = \sqrt{10000} = 100[/tex]

The probability that it contains more than 10010 particles is one subtracted by the p-value of Z when X = 10010, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10010 - 10000}{100}[/tex]

Z = 0.1

Z = 0.1 has a p-value of 0.5398.

1 - 0.5398 = 0.4602.

0.460 = 46% probability that 10 squared centimeters of dust contains more than 10010 particles.

More can be learned about the normal distribution at https://brainly.com/question/24537145

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