Dinitrogen monoxide has a structural formula of NNO and requires resonance structures in order to draw the Lewis structures of the molecule. Based on formal charge distributions, themostsignificant (stable) resonance structure for this molecule exhibits the order of formal charges for the 1st N, the central N, and the O atoms, respectively, as:

A. 0,+1,-1
B. -1,+1,0
C. -2,+3,-1
D. 0,0,0

You can draw the lewis structure for NNO 3 ways: With two double bonds N=N=O, with a triple bond between the N and O and single bond between the two N's, or a triple bond between the two N's and a single bond between the N and O.

The goal is to have formal charges that are as small as possible, to have no identical formal charges on adjacent atoms, and to have the most negative formal charge on the most electronegative atom. The most stable structure is the one with the triple bond between the two N's because it gives the formal charges 0, 1, and -1 respectively. Unlike the other two structures, the negative formal charge is correctly placed on O, the most electronegative atom.

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-11-13T07:00:18+01:00

Three resonance structures contribute to the structure of dinitrogen monoxide.

The resonance structure is invoked when a single structure can not sufficiently explain all the bonding properties of a compound. All the various contributing structures contribute to the final structure of the compound but not all to the same degree.

There are three resonance structures of dinitrogen monoxide. The most stable structure is always the structure that has the formal charges as -1, +1 and zero as shown.

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