The area of the sector is 86.81π mm²
Explanation:
Given:
Radius of the sector, 25mm
Angle, α = 50°
Area of the sector, A = ?
We know:
Area of the sector = [tex]\frac{\alpha }{360} X \pi r^2[/tex]
On substituting the value, we get:
[tex]A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2[/tex]
Therefore, the area of the sector is 86.81π mm²
