Answer:
[tex]n^2+6n+1[/tex]
Step-by-step explanation:
AB would be (n) * (2n + 6). We need to distribute the n, so we multiply the n by each term within the parentheses and add those products together:
AB = [tex]n(2n+6)=2n^2+6n[/tex]
C is just [tex]n^2-1[/tex] , and we subtract this from [tex]2n^2+6n[/tex]:
[tex]2n^2+6n-(n^2-1)=2n^2+6n-n^2+1=n^2+6n+1[/tex]
Thus, the answer is [tex]n^2+6n+1[/tex].
Hope this helps!
