Here are seven tiles: 1,1,3,3,3,5,5. Tom takes a tile at random. He does not replace the tile. Tom then takes a second tile. A) Calculate the probability that both tiles have the number 1 on them. B) calculate the probability on the second tile tom picks is greater than the first tile he takes.

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Answer:

a) 2/42

b)16/42

Step-by-step explanation:

a) 2/7 x 1/6 = 2/42

b) (1,2)  (1,3) (2,3)

   P(1,2) = 2/7 x 3/6 = 6/42

   P(1,3) = 2/7 x 2/6 = 4/42

   P(2,3) = 3/7 x 2/6 = 6/42

Add all = 6/42 + 4/42 + 6/42 = 16/42

The probability that both tiles have the number 1 on them is 1/21 and  the probability on the second tile tom picks is greater than the first tile he takes is 8/21

What is probability?

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

Here are seven tiles: 1,1,3,3,3,5,5.

Tom takes a tile at random.

P(both tiles have the number 1 on them) = (2/7)(1/6) = 2/42 =1/21

P(second tile tom picks is greater than the first tile he takes):

=  P(1,2) + P(1,3) + P(2,3)

= (2/7)(3/6) + (2/7)(2/6) + (3/7)(2/6)

= 16/42

or

= 8/21

Thus, the probability that both tiles have the number 1 on them is 1/21 and  the probability on the second tile tom picks is greater than the first tile he takes is 8/21

Learn more about the probability here:

brainly.com/question/11234923

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