Answer:
A. 1.47x10-3 m
Explanation:
The distance to the nth maximum from the central band is given by
[tex]y = n\dfrac{\lambda L}{d}[/tex]
where [tex]\lambda[/tex] is the wavelength of light, [tex]L[/tex] is the distance to the screen, and [tex]d[/tex] is the slit separation.
Now, the first maximum appears at [tex]n=1[/tex]; therefore, [tex]y[/tex] becomes
[tex]y = \dfrac{\lambda L}{d}[/tex]
and since in our case [tex]\lambda = 700*10^{-9} m[/tex], [tex]L = 1.58m[/tex], and [tex]d = 0.750*10^{-3}m[/tex], we get:
[tex]y = \dfrac{700*10^{-9} (1.58)}{0.750*10^{-3}m}[/tex]
[tex]\boxed{y=1.47*10^{-3}m.}[/tex]
which we see is choice A from the options.
