Given:
The given function is [tex]F(t)=4 \cdot \frac{1}{2^{3 t}}[/tex]
We need to determine the value of F(1)
Value of F(1):
The value of F(1) can be determined by substituting t = 1 in the function [tex]F(t)=4 \cdot \frac{1}{2^{3 t}}[/tex]
Hence, substituting t = 1 in the function [tex]F(t)=4 \cdot \frac{1}{2^{3 t}}[/tex], we get;
[tex]F(1)=4 \cdot \frac{1}{2^{3 (1)}}[/tex]
Simplifying the values, we get;
[tex]F(1)=4 \cdot \frac{1}{2^{3}}[/tex]
Simplifying the denominator, we have;
[tex]F(1)=4 \cdot \frac{1}{8}}[/tex]
Dividing the terms, we have;
[tex]F(1)=\frac{1}{2}[/tex]
Thus, the value of F(1) is [tex]\frac{1}{2}[/tex]
Hence, Option A is the correct answer.
